Word Problems

11 )

A sum of Rs 7000 is deposited in two schemes. One part is deposited in Scheme A which offers 8% rate of interest. Remaining part is
invested in Scheme B which offers 10% rate of interest compounded annually. If interest obtained in scheme A after 4 years is Rs 226 more than the interest obtained in scheme B after 2 years, find the part deposited in scheme B.

3700

3800

3900

4100

3600

View Solution

Answer :

(7000-x)*8*4/100 = x [ (1 + 10/100)2 – 1] + 226
70*8*4 – 32x/100 = 21x/100 + 226
2240 – 226 = 53x/100
2014 = 53x/100
So, x = Rs 3800

12 )

A work which is completed by 20 men in 8 days can be completed by 25 women 12 days. 16 men and 10 women start doing the work. After 3
days, they leave. If the remaining work is to be completed in 6 days by x number of men, find x.

11 men

13 men

19 men

17 men

16 men

View Solution

Answer :

20 men in 8 days so 16 men in 20 × 8/16 = 10 days and
25 women in 12 days so 10 women in 25 × 12/10 = 30 days
So in 3 days, they complete (1/10 + 1/30) × 3 = 2/5
So remaining work = 1 – 2/5 = 3/5
20 m 1 work in 8 days and x men 3/5 work in 6 days
So 20 × 8 × 3/5 = x × 6 × 1
So, x = 16 men

13 )

There are 140 tickets (numbered 1 to 140) in a bowl. Find the probability of choosing a ticket which bears multiple of either 3 or 7.

3/5

3/7

7/3

4/5

4/9

View Solution

Answer :

Number of multiples of 3 in 140 = 140/3 = 46
Number of multiples of 7 in 140 = 140/7 = 20
Number of multiples of 3×7= 21 in 140 = 140/21 = 6
So required probability = (46+20 – 6)/140 = 60/140 = 3/7

14 )

A 48 litres solution contains liquids water and milk in the ratio 3 : 5. How much amount of milk is to be added so that amount of milk is 70%
of the new solution?

12 litres

14 litres

15 litres

17 litres

21 litres

View Solution

Answer :

Water present in solution = 3/8 * 48 = 18 l
Milk present in solution = 5/8 * 48 = 30 l
Let x litres of milk to be added

Milk is to be 70% of new solution, so water is to be 30% of new solution. So
30/100 of new solution = Water present in new solution
30/100 * (48+x) = 18
So, x = 12 litres
OR
70/100 of new solution = Milk present in new solution
70/100 * (48+x) = 30+x
So, x = 12 litres

15 )

In a class, average age of 30 students is 18 years. If the age of 2 more students is taken into consideration, then the average of all students
gets increase by 1. Find the average of the ages of those 2 students.

View Solution

Answer :

30 students – 18
32 students – 19
So total age of those 2 students = 30×1 + 19×2 = 68
So average = 68/2 = 34

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